4x^(2/3)-35x^(1/3)-9=0

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Solution for 4x^(2/3)-35x^(1/3)-9=0 equation: 


x in (-oo:+oo)

4*x^(2/3)-(35*x^(1/3))-9 = 0

4*x^(2/3)-35*x^(1/3)-9 = 0

t_1 = x^(1/3)

4*t_1^2-35*t_1^1-9 = 0

4*t_1^2-35*t_1-9 = 0

DELTA = (-35)^2-(-9*4*4)

DELTA = 1369

DELTA > 0

t_1 = (1369^(1/2)+35)/(2*4) or t_1 = (35-1369^(1/2))/(2*4)

t_1 = 9 or t_1 = -1/4

t_1 = -1/4

x^(1/3)+1/4 = 0

1*x^(1/3) = -1/4 // : 1

x^(1/3) = -1/4

( -1/4 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 9

x^(1/3)-9 = 0

1*x^(1/3) = 9 // : 1

x^(1/3) = 9

x^(1/3) = 9 // ^ 3

x = 729

x = 729

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